Question

If a positive number exceeds its positive square roots by 12,then find the number

Answer 1

let the positive square root be   x

THE positive number =x²


given,x²=x+12


x²-x-12=0
x²-4x+3x-12=0

x(x-4)+3(x-4)=0


(x+3)(x-4)=0


x=-3,4

hence -3 is not positive square root



4 is the positive square root

the number is 4²=16

THE NUMBER IS 16

16-12=4
√16=4

hope helped

Answer 2

Answer:16

Step-by-step explanation:

this question is asking such no which square come after adding 12 .

Let the no be x^2 and sqaure root =x

X+12=x^2 sloving it come -3 and 4 since 4 is postive no

4^2 =16