Question

If a positive number 'n' when divided by 9 leaves a remainder 6 then what is the remainder when 3n + 2 is divided by 3?

Answer 1

Answer:

::2

Step-by-step explanation:

n is a multiple of 3

because when 'n' divides by 9 , the reminder is 6

9 and 6 are multiples of 3

3n+2divides by 3:::

3n is a multiple of 3

(3n=3×n)

so, 2 is the reminder

hope this will help u.

.....

please mark as BRAINLIEST........

Answer 2

The remainder when 3n + 2 is divided by 3 is 2

Given :

A positive number 'n' when divided by 9 leaves a remainder 6

To find :

The remainder when 3n + 2 is divided by 3

Solution :

Step 1 of 2 :

Find the number n

Here it is given that the positive number 'n' when divided by 9 leaves a remainder 6

Dividend = n

Divisor = 9

Remainder = 6

Let quotient = k

The number

= n

= Dividend

= Divisor × Quotient + Remainder

= (9 × k) + 6

= 9k + 6

Step 2 of 2 :

Find the required number

3n + 2

= 3(9k + 6) + 2

= 27k + 18 + 2

= 27k + 20

= 27k + 18 + 2

= 3(9k + 6) + 2

Now , 3(9k + 6) is completely divisible by 3

∴ 2 is the remainder when 3(9k + 6) + 2 is divided by 3

∴ 2 is the remainder when 3n + 2 is divided by 3

Hence the remainder when 3n + 2 is divided by 3 is 2

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ Apply the distributive property to create an equivalent expression. 5*(−2w−4)

https://brainly.in/question/33967867

2. Complete the following product (x-3)(x^(2)+3x+9)

https://brainly.in/question/25709643

#SPJ3