Question

If a potential difference of 230V is applied between the ends of 92 ohms resistance for 15 minutes.How much heat is produced?.What is the intensity of current inthe circuit?​

Answer 1

Answer:

V = 230v r = 92 ohm. t = 15 min = 900 sec

The amount heat produced is H=V²t/r

=(230)²×900/92J

=517,500 J

The intensity of current in the circuit I = V/r

=230/92 A

=2.5 A