Question

if a power 2 + 6 a + x =(a+3) power 2 , find the value of x
Plz solve it fast i will give u 20 points​

Answer 1

Question:

• $\large{\sf{a²+6a+x\:=\:(a+3)²}}$

To Find:

• Value of x ?

Solution:

We are given equation is a² + 6a + x = (a+3)²

Here, we can algebraic identities (a+b)² (i.e a² + b² + 2ab) in RHS for expanding.

Where,

• a = a
• b = 3

Therefore,

a² + 6a + x = (a+3)²

→ a² + 6a + x = a² + 3² + 2×a×3

→ a² + 6a + x = a² + 9 + 6a

→ $\small{\sf{\cancel{a²+6a}+x\:=\: {\cancel{a²}}+9 + {\cancel{6a}}}}$

→ x = 9

Therefore,

• Value of x = 9

Verification:

a² + 6a + x = (a+3)²

[Putting x = 9]

→ a² + 6a + 9 = a² + 3² + 2×a × 3

→ a² + 6a + 9 = a² + 9 + 6a

LHS = RHS

$\large{\bf{\green{Verified✓}}}$

Answer 2

Answer is in the attachment