Question

If a ∆ PQR is right angled at Q, then find the value of sin(P+R)

Answer 1

Answer:

sin(90)=1

Step-by-step explanation:

sum of three angle of triangle =180

P+Q+R =180

As Q = 90

P+R=180-Q

P+R=180-90

P+R=90

sin(90)=1

Answer 2

The value of sin(P+R)=1 .

Explanation:

Given : ∆ PQR is right angled at Q.

i.e. The measure of ∠Q= 90°.

Angle sum property : The sum of all angles in a triangle = 180°

So in Δ PQR , we have

∠P+∠Q+∠R=180°     ( By Angle sum property)

⇒ ∠P+90°+∠R=180°

⇒∠P+∠R=180° -90°

⇒∠P+∠R=90°

Now , the value of $\sin(P+R)=\sin (90^{\circ})=1$

Therefore , the value of sin(P+R)=1 .

# Learn more :

In ∆PQR, right angled at Q, PQ = 4 cm and RQ = 3 cm. Find the values of sin P, sin R, sec P and sec R.

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