Question

if a pressure of 378 atm is exerted on a circular cross sectio of radius 0.1 mm , what is the force exerted on the area

Answer 1

Force = Pressure × Area
= P × πR²
= 378 atm × 101325 Pa/atm × π × (0.1 × 10^-3 m)²
= 2.0 N

Force extered is 2.0 N

[Note: I converted Pressure in atm to Pa and radius in mm to m]

Answer 2

378 atm x 101.325 = 38,300 kPa which means 38,300 kN per m2.

A section with a radius of 0.1 mm has an area of 3.14 x 10^-8 m2

The force applied will be 38.3x10^6 x 3.14x10^-8 = 1.2 Newton