if a pressure of 378 atm is exerted on a circular cross sectio of radius 0.1 mm , what is the force exerted on the area
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Answered by
70
Force = Pressure × Area
= P × πR²
= 378 atm × 101325 Pa/atm × π × (0.1 × 10^-3 m)²
= 2.0 N
Force extered is 2.0 N
[Note: I converted Pressure in atm to Pa and radius in mm to m]
= P × πR²
= 378 atm × 101325 Pa/atm × π × (0.1 × 10^-3 m)²
= 2.0 N
Force extered is 2.0 N
[Note: I converted Pressure in atm to Pa and radius in mm to m]
Answered by
35
378 atm x 101.325 = 38,300 kPa which means 38,300 kN per m2.
A section with a radius of 0.1 mm has an area of 3.14 x 10^-8 m2
The force applied will be 38.3x10^6 x 3.14x10^-8 = 1.2 Newton
A section with a radius of 0.1 mm has an area of 3.14 x 10^-8 m2
The force applied will be 38.3x10^6 x 3.14x10^-8 = 1.2 Newton
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