Question

If a principal amounts to Rs. 3150 in 4 years at the rate of 10% p.a. simple interest, what is the principal?
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Answer 1

Solution:

Amount(A)=RS.3150

Time(T)=4 years

Rate(R)=10%

Principal(p)=?

Now,

P=A×100/100+TR

=3150×100/100+4×10

=Rs.3190

So, The principal is Rs.3190.

HOPE THIS HELPS...

Answer 2

Given :

• Amount = Rs.3150
• Rate = 10 %
• Time = 4 years

To Find :

• Principal = ?

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SolutioN :

$\dag$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ Principal = \dfrac{Amount \times 100}{100 + Rate \times Time} }}}}}$

$\dag$ Calculating the Principal :

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Principal = \dfrac{Amount \times 100}{100 + Time \times Rate} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Principal = \dfrac{3150 \times 100}{100 + 4 \times 10} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Principal = \dfrac{315000}{100 + 4 \times 10} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Principal = \dfrac{315000}{100 + 40} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Principal = \dfrac{315000}{140} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Principal = \cancel\dfrac{315000}{140} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{\pmb{\sf { Principal = Rs. \; 2250 }}}}} \; {\pmb{\green{\bigstar}}} \\ \\ \\ \end{gathered}$

$\therefore \;$ The Principal is Rs.2250 .

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