If a producer claims that, the company produces marbles, having mean 10 mm and standard deviation of 1 mm. Now if you take 49 marbles randomly and found that the mean of this sample is 9 mm. Can you reject the null hypothesis at 1% significance level?
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Answer:
H₀ : μ = 10
Hₐ : μ ≠ 10
N=49
Mean=9
z= mean - μ / s.d.
z= (9-10) /( 1/√49)
z = -7
level of significance = 1%
Since , calculated value is less than the critical value . Therefore , we reject the null hypothesis .
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