If a projectile at 300 to the horizontal reaches the ground two seconds after its projection, the magnitude of change in velocity in that interval is (g = 9.8 m/sec2)
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Let in 2s body reaches upto point A and after one more sec upto point B
Total time of ascent for a body is given 3s
i.e., t=
g
usinθ
=3
∴usinθ=10×3
usinθ=30...(i)
Horizontal component of velocity remains always constant
ucosθ=vcos30
o
...(ii)
for vertical upward motion between point O and A
vsin30
o
=usinθ−g×2=30−20 (Using v=u−gt)
∴v=20m/s
Substituting this value v, we get Eq. (ii)
ucosθ=20cos30
o
...(iii)
from Eqs (i) and (iii)
u=20
3
m/s,;θ=60
o
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