Question

If a projectile is launched at 45° with
velocity 100 m/s, it hits the target. It will
have double the range in its velocity is
(a) 200 m/s (b) 141.4 m/s
(c) 173.2 m/s (d) 400 m/s​

Answer 1

Answer:

See the above Explanation.

Thanks.

Answer 2

Concept

A projectile is an object that is thrown into space and is only affected by gravity. The main force acting on the projectile is gravity.

Given

The degree of projectile given is 45°

The velocity given is 100m/s

Find

We have need to find the target . It will have double the range in its velocity

Solution

The projectile is launched at 45°

The velocity is 100m/s

We all know that Range of the velocity can be found by the formula

R = u^2 sind 2(theta)/g

Where R2 = 2R [A+Q]

u2^2Sin2(theta) = 2u^2

Hence the resultant will be U2=2u1 = 200m/s

Therefore the main force on the projectile and its gravity

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