Question

If a projectile is launched at 45° with velocity 100 m/s, it hits the target. It will have double the range in its velocity is (a) 200 m/s (b) 141.4 m/s (c) 173.2 m/s (d) 400 m/s

give answer with explanation please​

Answer 1

Answer:

y=xtanθ−

2u

2

cos

2

θ

gx

2

2=x−

2×10

2

×

2

1

10×x

2

=x−

10

x

2

2=x−

10

x

2

⇒x=5±

5

⇒d=x

1

−x

2

=2

5

=4.47m

firsthurdleisatx

1

=5−

5

=2.75m

Explanation:

Thank you