Question

If a proton and a -particle are accelerated through the same
potential difference, the ratio of de-Broglie wavelengths ????ₚ
and ????α is
(a) 3 (b) 2 √2
(c) 1 (d) 2

Answer 1

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hence the the value of eV or electron volt will be 3eV.

Now, to use the formulae to find wavelength = h/ V(2meV).

Where, let mass of proton be mp then mass of berelium will be 9mp.

Now, putting the values of m, and eV in the equation we get h//(2*9m*3eV).

Thus, the ratio of wavelengths of boron to that of the neutron will be 1/3/3.

This we can find by dividing the wavelength of normal neutron to that of wavelength of berelium.

Answer 2

Answer:

hence the the value of eV or electron volt will be 3eV.

Now, to use the formulae to find wavelength = h/ V(2meV).

Where, let mass of proton be mp then mass of berelium will be 9mp.

Now, putting the values of m, and eV in the equation we get h//(2*9m*3eV).

Thus, the ratio of wavelengths of boron to that of the neutron will be 1/3/3.

This we can find by dividing the wavelength of normal neutron to that of wavelength of berelium.

Explanation:

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