If a proton had a radius R and the charge was uniformly distributed, calculate using Bohr theory, the ground state energy of an H-atom when R=10 Armstrong
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put the value and find it by this formula
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radius of atom => R =0.0529*n^2/z
and
Energy = 13.6*z^2/n^2
dividing both the eqns. we get,
r/E = 0.0529/13.6z
E = r*13.6*z/0.0529 => 10*10^-10*13.6*1/0.0529 => 2.57 * 10^-7 J
HOPE THIS HELP....
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