Question

If a proton is placed in a uniform electric field, what would be the magnitude of the field if the electrostatic force acting on the proton is just to balance its weight? (take g as 9.8 m/s2, e as 1.60×10-19C and mass of proton as 1.67×10-27kg)

Answer 1

Answer:

E = 1.08 ×$10^{-7}$

Explanation:

Mass of proton (m) = 1.67 ×$10^{-27}$ kg

Charge on proton (Q) = 1.60 ×$10^{-19}$ C

Now , force on proton due to an electric field (F ) = QE

This force must balance the weight of the proton.

So, F = mg

or QE = mg

So, E = mg/Q

or E = 1.67 ×$10^{-27}$ kg × 9.8/ 1.60 ×$10^{-19}$ C

E = 1.08 ×$10^{-7}$

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