Question

If a proton moves at 7×106 m/s through a uniform 3T magnetic field, find the force experienced by the particle.​

Answer 1

Answer:

If a proton moves at $7*10^{6}$ m/s through a uniform magnetic field of intensity 3T, the force experienced by the particle is $33.6*10^{-13} N$

Explanation:

• When a particle with charge $q$ moving with velocity $V$ through the magnetic field by making an angle $\alpha$ with the magnetic field, the particle experiences a force called Lorentz force, which is given by the formula

                                                 $F=qVB sin\alpha$

From the question, we have given

velocity of proton $V=7*10^{6}m/s$

the intensity of the magnetic field $B=3T$

the charge of the proton $q=1.6*10^{-19}C$

since the angle is not given assume the angle as $\alpha =90$ (default case)

substituting these values to get force

$F=1.6*10^{-19}*7*10^{6}*3=33.6*10^{-13}N$