Question

if A€Q and B is an odd natural number, then A+√B is a rational number. is that true?
don't answer for points...if I like the answer,I will make u a brainlist! ​

Answer 1

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Answer 2

hey mate i am giving you a hint

We now introduce a third method of proof, called proof by contra- diction. ... This conditional statement being false means there exist numbers a and b ... if P is really true then this contradicts our assumption that P is false. ... Recall that a number is rational if it equals a fraction of two ... the contradiction b is even and b is odd.

If a and b are rational numbers, b = 0, and r is an irrational number, then prove that ... Prove that if a, b, and c are integers and a2 + b2 = c2, then at least one of a and b is even. ... We divide into two cases: c is even, or c is odd. If c is ... However, we know that it's irrational, and this is a contradiction

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