if a÷q-r=b÷r-p=c÷p-q,let us show that a + b + c = 0 = pa + qb+ rc
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Answer:
Step-by-step explanation:
Let a/q−r=b/r−p=c/p−q=k
q/q−r=k (on multiplying by P)
pa=k(pq=pr)………….i
In the same way we can write
qb=k(qr−qp)………….ii
and fc=k(rp−rq)……………iii
on adding eq i, ii and iii
pa+qb+rc=k(p−pr+qr−qp+rp−rq)
pa+qb+rc=0
Hence a+b+c=pa+qb+rc
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