Question

if a/q-r=b/r-p=c/p-q let us show that a+b+c=0=pa+qb+rc.​

Answer 1

Answer:

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Step-by-step explanation:

a/(q-r) = b/(r-p) = /(p-q) = k " (let)" [k ne 0]

<br>

:. A = k ( q - r), b = k (r -p) , c = k (p -q)

<br>

:. A + b + c = k (q - r) + k (r - p) + k (p -q)

<br>

= k (q - r + r - p + p - q) =k xx 0 = 0

. <br> Again ,

pa + qb + rc = p.k (q - r) + q.k (r - p) + r.k (p-q)

<br>

= k (pq - pr+qr - pq + pr -qr)

<br>

= k xx 0 = 0

. <br>

:. a + b + c = 0 = pa + qb + rc