If a quadratic polynomial y=ax2+bx+c intersects x axis at alpha and bita, then?
Answers
Answered by
7
Answer:
alpha = [-b + sqrt(b^2 - 4ac)]/2a
beta = [-b - sqrt(b^2 - 4ac)]/2a
Step-by-step explanation:
A quadratic equation has a graph of a parabola. If the quadratic polynomial y=ax2+bx+c intersect x axis at two points than , it has two roots .
This is because number of roots of a quadratic polynomial is equal number of points it cuts x axis .
So, here y=ax2+bx+c intersect x axis at two points so, it has two roots alpha and beta .
Value of alpha = [-b + sqrt(b^2 - 4ac)]/2a
Value of beta = [-b - sqrt(b^2 - 4ac)]/2a
Answered by
2
Answer:
Step-by-step explanation:
Concept:
The roots of the quadratic eqquation ax²+bx+c=0 are given by
since the polyniomial y=ax²+bx+c intersects x axis, y=0
This implies, ax²+bx+c=0
Then,
Therefore, the coordinates of are
Similar questions