if a Quadrillater ABCD , A=60 ,B=75 , D=95 find out C=
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In quadrilateral ABCD, ∠A = 60∘ and ∠B:∠C:∠D=2:3:7 [Given].
Let ∠B,∠C,∠D are 2x∘ , 3x∘ and 7x∘.
⇒ ∠A+∠B+∠C+∠D=360∘ [Sum of all angles of quadrilateral is 360∘]
⇒ 60∘+2x∘+3x∘+7x∘ = 360∘
⇒ 12x∘ = 360∘−60∘
⇒ x∘ =
Now, ∠D=7x∘.
Substitute value of x we get,
⇒ ∠D=7×25o
∴ ∠D=175∘.
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