if a radio and bulb each of resistances 3 ohm are connected in series to 12 volts battery the potential difference across each will be
Answers
Answered by
9
Answer:
BRO IT IS A VERY EASY QUESTIONS.......
WE KNOW , IN A SERIES. CURRENT REMAINS SAME ...
R1= 3
R2= 3
R EQUIVALENT= R1+ R2 ( SERIES)
= 6 Ohm
EMF = 12 V
I (CURRENT ) =. E / R
= 12 / 6
= 2 AMPERE
P.D ALONG THE RADIO IS V = IR
= 6 V.
AND WHICH IS ALSO SAME FOR THE RESISTANCE. = 6V
HOPE IT HELPS...@AMINUL. HOQUE.
Similar questions