If a radius of a circle is increased by 100 percent than what will be the percentage increase in area
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Let the radius r units
Area = πr² = 22r²/7
100% of r increase
= r + 100% of r
= r + (100/100)×r
= r + r
= 2r units
New radius = 2r units
New area = π (2r)²
= 22/7 × 4r²
= 88r²/7
Difference in the area = 88r²/7 - 22r²/7
= (88r² - 22r²)/7
= 66r²²/7
Percentage in increase in area = [(66r²/7) / (22r²/7)] × 100
= [66r² / 22r²] × 100 [ 7 on both numerator and denominator get cancelled]
= 3× 100
= 300%
Area = πr² = 22r²/7
100% of r increase
= r + 100% of r
= r + (100/100)×r
= r + r
= 2r units
New radius = 2r units
New area = π (2r)²
= 22/7 × 4r²
= 88r²/7
Difference in the area = 88r²/7 - 22r²/7
= (88r² - 22r²)/7
= 66r²²/7
Percentage in increase in area = [(66r²/7) / (22r²/7)] × 100
= [66r² / 22r²] × 100 [ 7 on both numerator and denominator get cancelled]
= 3× 100
= 300%
Answered by
0
300per I write direct answer
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