If a radius of a circle is increased by 5% then percentage increase in its area
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let the original radius of circle be ' r '
original area :
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original area of circle = πr^2
if the radius is increased by 5 % then Find the new radius of circle .
new radius=r + 5%of r = r + 0.05r=1.05r
Find the new area :
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new area of circle = π ( 1.05r )^2
= 1.1025πr^2
Find the increase :
increase = new area - original area
= 1.1025πr^2 - πr^2 = πr^2 ( 1.1025 - 1 )
= 0.1025πr^2
Find the increase% :
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increase% = increase × 100/ original area
= 0.1025 πr^2 × 100 / πr^2
= 0.1025 × 100 = 10.25 %
therefore,
area of circle will be increased by 10.25 % .
short cut method :
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area of circle = πr^2
r^2 = r × r , let r = 5 , r = 5
increase in area = r + r + [( r × r )/ 100]
= 5 + 5 + [ ( 5 × 5 )/ 100 ]
= 10 + ( 25/ 100 ) = 10 + 0.25
= 10.25 %
Answer : 10.25 %
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original area :
------------------
original area of circle = πr^2
if the radius is increased by 5 % then Find the new radius of circle .
new radius=r + 5%of r = r + 0.05r=1.05r
Find the new area :
--------------------------
new area of circle = π ( 1.05r )^2
= 1.1025πr^2
Find the increase :
increase = new area - original area
= 1.1025πr^2 - πr^2 = πr^2 ( 1.1025 - 1 )
= 0.1025πr^2
Find the increase% :
--------------------------
increase% = increase × 100/ original area
= 0.1025 πr^2 × 100 / πr^2
= 0.1025 × 100 = 10.25 %
therefore,
area of circle will be increased by 10.25 % .
short cut method :
------------------------
area of circle = πr^2
r^2 = r × r , let r = 5 , r = 5
increase in area = r + r + [( r × r )/ 100]
= 5 + 5 + [ ( 5 × 5 )/ 100 ]
= 10 + ( 25/ 100 ) = 10 + 0.25
= 10.25 %
Answer : 10.25 %
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