If a radius of a right circular cone is halved and its height is doubled, the volume will remain unchenged.
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Answered by
49
let the radius be r and and height be h
so the the volume is equal to 1/3πr²h
when Radius is halved and height is doubled
the the volume is equal to 1/3π(r/2)²×2h
=1/3πr²/4×2h
=1/3πr²/2×h
so the volume becomes half.
so the the volume is equal to 1/3πr²h
when Radius is halved and height is doubled
the the volume is equal to 1/3π(r/2)²×2h
=1/3πr²/4×2h
=1/3πr²/2×h
so the volume becomes half.
Answered by
9
Answer:
let the radius be r and and height be h
so the the volume is equal to 1/3πr²h
when Radius is halved and height is doubled
the the volume is equal to 1/3π(r/2)²×2h
=1/3πr²/4×2h
=1/3πr²/2×h
so the volume becomes half.
@hopeless
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