if a radius of a sephere is doubled,what iz the ratio of the volume of the first sphere to that of the second sphere?
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it becomes 1/8 as 4/3π gets cancelled
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HEY YOUR ANSWER IS GIVEN BELOW
$$$$$$$$$$$$$$$$$$$$$$$$$$$$$
VOLUME OF SPHERE 1 = (4/3) π r^3
VOLUME OF SPHERE 2( NEW SPHERE FOUND BY DOUBLING THE RADIUS) = (4/3) π (2*r)^3
V1 : V2 = (4/3) π r^3 : (4/3) π (2*r)^3
SO THE RATIO OF V1:V2 = 1:8
PLEASE MAKE AS BRAINLIEST
$$$$$$$$$$$$$$$$$$$$$$$$$$$$$
VOLUME OF SPHERE 1 = (4/3) π r^3
VOLUME OF SPHERE 2( NEW SPHERE FOUND BY DOUBLING THE RADIUS) = (4/3) π (2*r)^3
V1 : V2 = (4/3) π r^3 : (4/3) π (2*r)^3
SO THE RATIO OF V1:V2 = 1:8
PLEASE MAKE AS BRAINLIEST
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