if a radius of the sphere is 1/2 . then what is the decrease in its surface area?
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Answer:
helping hand!!!!!your answer is 75 percent
Step-by-step explanation:
radius=r
surface area=4pier^2
radius is=1/2
so, surface area=4pie(r/2)^2
decrease in surface area=4pier^2-1pier^2=3pier^2
percentage=3pier^2/4pier^2×100
=75percentage
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