If a raindrop with a mass of 0.05 g falls with constant
velocity, the retarding force of atmospheric friction is
(neglect density of air):
A Zero
B. 49 dynes
C. 490 N
D. 49 N
Answers
Answered by
1
Answer:
Work done = mgh
m = mass of drop = 0.1 g = 0.00001 kg
g = 9.8 m/s
h = 100 m
work done = 0.00001 x 9.8 x 100
= 0.098 J
THANK YOU
Answered by
1
Answer:49 dye
Explanation:
Beck 0.05 x 980 = 49 dyes
Similar questions