Question

If a random variable has a poisson distribution such that p(1)=p(2), find mean of the distribution

Answer 1

Answer:

IDK

Step-by-step explanation:

I DON'T KNOW.. SORRY.. BUT, WILL SURELY EXPLAIN YOU ON MONDAY... TODAY I'M A BIT BUSY... SO... I HOPE, YOU FORGAVE ME..!

Answer 2

Given: The Poisson distribution of a random variable is such that p(1)=p(2)

To find: The mean of the distribution.

Solution:

The formula for the probability of Poisson distribution is given by:

P(X,μ) = $\frac{(e^-μ)(μ^-x)}{x!}$

It is given that,

P(1) = P(2)

⇒ $\frac{e^-μ μ^1}{1!} = \frac{e^-μ μ^-2}{2!}$

⇒ μ = 2

Final answer:

Hence, the mean is = 2.