Question

if a random variable X has a poisson distribution with mean 0.4,then P(X<=1) is​

Answer 1

sorry dear don't know the answer

Answer 2

Answer:

The poisson probability P(X≤1) is 0.9384480  

Step-by-step explanation:

The Poisson Probability is given by

$P(x,m)= \frac{m^{x} e^{-m} }{x!}$

x = random variable

m = poisson distribution mean

Given that m = 0.4

We know that

$P(X=k) = \frac{m^{k} e^{-m} }{k!}$

To find P(X≤1)

Consider,

P(X≤1) = P(X=0) + P(X=1)

          $= \frac{(0.4)^{0} e^{-(0.4)} }{0!}+\frac{(0.4)^{1} e^{-(0.4)} }{1!}$

          = 0.67032 + 0.2681

P(X≤1) = 0.93844

Therefore the Poisson probability  P(X≤1) is 0.9384480