Question

If a rational number and a,b, c are all different integers, then prove that :

$x{}^{ a-b } \times x {}^{b - a} = 1$
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

LHS=x^a-b× x^b-a. =x^a-b+b-a. =x^0. =1 therefore LHS=RHS