Question

If a reactant 'A' is tetramerised, then the van't Hoff
factor (i) is equal to
(1) 0.75
(2) 0.20
(3) 0.15
(4) 0.25
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Answer 1

Answer:

Vant hoff factor is the ratio of number of particles after association to the number of particles before association.

$i = \frac{obseved \: colligative \: property}{calculated \: colligative \: property \: }$

4A=A4

Before association: number of moles = 4

Before association: number of moles = 4After association( tetramerization) : number of moles = 1

$i = \frac{1}{4} = 0.25$

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Answer 2

The van't Hoff factor (i) is equal to 0.25

Explanation-

Van't Hoff's factor is the ratio of observed colligative property to the calculated Colligative property.

$i=\frac{\text {observed colligative property}}{\text {Calculated Colligative property}}$

$4X\rightarrow X_4$

Calculated Colligative property = total moles before dissociation = 4

observed colligative property = Total moles after dissociation= 1

Thus $i=\frac{1}{4}$

$i=0.25$

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