If a reaction HNO3 is reduced to NO , the mass of HNO3 absorbing 1 mole of electron would be ?
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We have HNO3 ------> NO, The change in oxidation number is +3; Equivalent mass of HNO3 = (1+14+ 16 +16 +16) / 3 = 63/3 = 21.0 g (around) so 21.0 g is the answer.
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