if a rectangle has a length of 12 cm and width of 5 cm. find the measure of its diagonal
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by pythagorous theorum
diagonal^2=length^2+breadth^2
=12^2+5^2
=144+25
=169
so diagonal^2=169
diagonal=square root of 169
=13cm ans
diagonal^2=length^2+breadth^2
=12^2+5^2
=144+25
=169
so diagonal^2=169
diagonal=square root of 169
=13cm ans
khushi6529:
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As it forms a right angled triangle
Therefore AB^2+BC^2=AC^2
12^2+5^2=AC^2
AC^2=144+25
AC^2=169
AC=13
Therefore diagonal is 13cm
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