if a rectangle solid has length , breadth and height in the ratio 4:5:6 and its total surface area be 3700 m. square then find its length, breadth and height
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let the ratio be 4x 5x 6x
Tsa =3700m ^2
tsa =2(lb+lh+bh)
3700=2 [(4x×5x )+(5x×6x)+(6x×4x)
3700=2 [20x sq +30x sq+ 24x sq]
3700=2×74x sq
3700=148x sq
3700/148=x sq.
x =_/25
x =5m
l=4x =4×5=20m
b=5x=5×5=25m
h=6x=6×5=30m
Tsa =3700m ^2
tsa =2(lb+lh+bh)
3700=2 [(4x×5x )+(5x×6x)+(6x×4x)
3700=2 [20x sq +30x sq+ 24x sq]
3700=2×74x sq
3700=148x sq
3700/148=x sq.
x =_/25
x =5m
l=4x =4×5=20m
b=5x=5×5=25m
h=6x=6×5=30m
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