Question

If a rectangle with length units and width units is inscribed in a circle of radius 5 units, what is the value of a + b?

Answer 1

The diameter is 5*2=10cm

The diameter=diagonal of rectangle.

$d=\sqrt{a^2+b^2}$

$10=\sqrt{a^2+b^2}$

Hence a should be 8 and b=6 satisfies the equations

$10=\sqrt{6^2+8^2}$

$10=\sqrt{100}$

Other values exist but a,b are 8,6 if the lengths are natural numbers.