If a regular polygon has 44 diagonals find the no of sides
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Answered by
1
The number of diagonals for an n sided polygon = [n(n-3)]/2
therefore, 44 = [n(n-3)]/2
=> n*n - 3n - 88 = 0
=> n = 11
therefore, the no. of sides = 11
therefore, 44 = [n(n-3)]/2
=> n*n - 3n - 88 = 0
=> n = 11
therefore, the no. of sides = 11
Answered by
3
Hi friend,
The answer is 11.Please find the complete explanation in the attached image.
Hope this helps. . Cheers. .
If you understood from it well, then please please mark as the BRAINLIEST and also say a thanks.
Thanks.
The answer is 11.Please find the complete explanation in the attached image.
Hope this helps. . Cheers. .
If you understood from it well, then please please mark as the BRAINLIEST and also say a thanks.
Thanks.
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