Physics, asked by ihjidni, 24 days ago

If a resting car's velocity for 1 to 5sec is respectively 2m/s, 6m/s, 12m/s, 4m/s, 1m/s then for 5sec distance traveled, s =25m and acceleration is 0.2m/s^2. But if you use ut+1/2at^2 then s=2.5m why?

Answers

Answered by shalvipandey720
0

Answer:

Acceleration is the rate of change of velocity.

So in the question it's given that the rate of change of velocity is 20 m/s so it should be 20m/s^2

But I think I misunderstood the question so below is what you can do to get the acceleration.

If you have velocity V1 at a time suppose T1 and velocity V2 at a different time T2 then

Acceleration = (V2-V1) /(T2-T1)

So if the speed change 20 m/s in 5 sec then

Acceleration = (20-0)/(5–0)

= 4 m/s^2

If it helped do upvote.

Thanks

Explanation:

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