If a rhombus has a perimeter of 68 and one diagonal of 30, what is the length of the other diagonal? What is the area of the rhombus?
Diagonal =
Area =
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We know then that each side of the rhombus is 68/4 = 17. Now, the diagonals of the rhombus bisect each other at right angles. We then have 4 right triangles, each with one leg = 30/2 = 15 and the hypotenuse = 17. So, half the other diagonal is 8 => the second diagonal's length is 16.
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