if a rhombus is reshaped such that one of its diagonal increases by 2 % wle other diagonal decreases by 2 % find the percentage change in the area of Rhombus
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let the diagonals be x and y cm.area(orinigal)=1/2.diagonal 1 . diagonal 2 =1/2xy.now x is reduced by 2 percent. new diagonal = x-2/100.x =49x /50. y is increased by 2percent. New diagonal =y+2/100.y=51y/50. new area =1/2 . diagonal 1 .diagonal 2(both are new diagonal). new area = 1/2.49x/50.51y/50=2499xy/5000.change area = 2499xy/5000-1/2xy =-xy/5000.change percent = change/original .100 =-xy/5000/1/2xy.100=-1/25=0.04percent
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