If a rhombus with side x has an area of x*x /2, then length of its largest diagonal is √p+√q x p*p+q*q
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Area of rhombus = 1/2 × product of diagonals So A = 1/2 ... so by pythagoras theorem, (P/2)² + (q/2)² = (sides... ... Area=1/2xy(x and y are lengths of diagonals ...
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