Question

If a right circular cone hs radius 4 cm and
slant height 5 cm then what is its volume?​

Answer 1

ANSWER →

$v = \pi\:r{}^{2} \frac{h}{3} \\ l = \sqrt{r{}^{2}+h {}^{2}} \\ v = \frac{1}{3} \pi \: r {}^{2} \sqrt{l {}^{2} - r {}^{2}} \\ \frac{1}{3} \times \pi \times 4 {}^{2} \times \sqrt{5 {}^{2} - 4 {}^{2} } \\ = 50.26$

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Answer 2

Answer:

Please refer to the answer below.

Step-by-step explanation:

Volume of cone = 1/3πr²h

Given that,

• Slant Height (l) = 5cm
• Radius of the cone = 4cm

So we need to find the hieght of the cone to get the answer,

height = √l²-r²

ie, √5²-4² = √25-16 = √9 = 3

Now volume will be,

1/3πr²h

= 1/3 x 22/7 x 4² x 3

= 1/3 x 22/7 x 16 x 3

= 1 x 22/7 x 16 ( 1/3 and 3 is cancelled)

= 22/7 x 16 = 352/7 = 50.285