If a right circular cone of height 24 cm has a volume of 1232 cm3, then the area of its curved surface
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1
Volume of cone=1/3πrsquare×5
1232=1/3×22/7×rsquare×24
rsquare=1232×3×7/1×22×24
rsquare =49
therefore r=7
curved surface area of cone=πr(r+l)
=22/7×7(7+24)
=22/7×7×31
=682
1232=1/3×22/7×rsquare×24
rsquare=1232×3×7/1×22×24
rsquare =49
therefore r=7
curved surface area of cone=πr(r+l)
=22/7×7(7+24)
=22/7×7×31
=682
Answered by
5
GiVen :-
- height of the cone =24 cm
- radius = r cm {say} then
1/3 πr²h = 1232 cm³ [given]
→ r² = 1232 × 3 × 7 /22 × 24 = 49
→ r = 7cm
now , slant height of the cone
= √[7]² + [24]² = 25
surface area of the cone :-
= πrl =22/7×7×25 =550cm²
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