If a right circular cone of height 24cm has a volume of 1232cm3 then the area of curved surface is
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Given the height of the cone = 24cm
Volume of the cone = 1232cm³
Therefore 1/3πr²h = 1232cm³
>> 1/3 × 22/7 × r² × 24 = 1232cm³
>> 528/21 × r² = 1232cm³
>> r² = 1232/1 × 21/528
>> r² = 25872/21
>> r² = 49
>> r = √49
>> r = 7cm
Now, length (slant height) of the cone = √(7²+24²)
= √(49+576)
= √625
= 25cm
CSA (curved surface area) of the cone = πrl
= 22/7 × 7 × 25
= 22 × 25
= 550cm²
Given the height of the cone = 24cm
Volume of the cone = 1232cm³
Therefore 1/3πr²h = 1232cm³
>> 1/3 × 22/7 × r² × 24 = 1232cm³
>> 528/21 × r² = 1232cm³
>> r² = 1232/1 × 21/528
>> r² = 25872/21
>> r² = 49
>> r = √49
>> r = 7cm
Now, length (slant height) of the cone = √(7²+24²)
= √(49+576)
= √625
= 25cm
CSA (curved surface area) of the cone = πrl
= 22/7 × 7 × 25
= 22 × 25
= 550cm²
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