Question

If a right circular cone shape building has radius 8m and slant height 17m, then what is its volume?

Answer 1

Given

⇒Radius = 8m

⇒Slant Height = 17m

To find

⇒Volume of Right circular cone

Formula

⇒Volume = πr²h/3

We have to find Height(h)

Formula

⇒l² = r² + h²

Now Put the value , we get h

⇒(17)² = (8)² + h²

⇒289 = 64 + h²

⇒h² = 289 - 64

⇒h² = 225

⇒h = 15 m

Now Put the value on formula

⇒Volume = πr²h/3

⇒Volume = 22/7 × 8×8×15/3

⇒Volume = 22/7 × 64 × 5

⇒Volume = 22/7 × 320

⇒Volume = 3.14 × 320

⇒Volume = 1004.8 cm³

Answer

⇒Volume of cone is  1004.8 cm³

Answer 2

Answer:

Given :-

Radius = 8 m

Slanght height = 17 m

To Find :-

Volume

Solution :-

At first we need to Find Height of the cone

$\sf \: {l}^{2} = {r}^{2} + {h}^{2}$

$\sf \: {17}^{2} = {8}^{2} + {h}^{2}$

$\sf \: {17}^{2} - {8}^{2} = {h}^{2}$

$\sf \: 289 - 64 = {h}^{2}$

$\sf \: 225 = {h}^{2}$

$\sf \: \sqrt{225} = {h}^{2}$

$\sf \: 15 = h$

Now

$\sf \: Volume = \dfrac{1}{3} \pi {r}^{2} h$

$\sf \:Volume = \dfrac{1}{3} \times \dfrac{22}{7} \times (8) {}^{2} \times 15$

$\sf \: Volume = \dfrac{1}{3} \times \dfrac{22}{7} \times 64 \times 15$

$\sf \: Volume = \dfrac{22}{7} \times 64 \times 5$

$\sf \: Volume = \dfrac{7040}{7}$

$\sf \: Volume = 1005 \: c {m}^{3}$