Math, asked by mithileshpandey211, 11 months ago

If a right triangle has area 28 and hypotenuse 12, what is its perimeter?

Answers

Answered by kunalakriti2016
0

Answer:

Let the triangle ABC a right triangle right angled at B. Then,

ar (Abc)= 28 uniy^2...............(i)

Attachments:
Answered by shaunalanjoseph
0

Hello,

Answer:

The perimeter is 28.

Step-by-step explanation:

Let the other two sides be 'a' and 'b'.

\frac{1}{2} *a*b = 28  (given, area of triangle)  -(1)

and..

a^{2} + b^{2} = 12^{2} = 144 (using pythagoras theorem) -(2)

adding (1) and (2)

a^{2} + b^{2} + 2ab = 144 + 2*56\\\\(a+b)^{2} +2ab - 2ab = 256\\\\a+b=\sqrt{256} =16

thus perimeter = a+b+(hypotenuse) = 16 + 12 = 28

Hope I Helped.

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