If a rock fell off of a cliff, how fast would the rock be going after 2 seconds? 1 point a) 2m/s 1.96m/s c) 7.5m/s d) 19.6m/s.
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Given : a rock fell off of a cliff,
To Find : how fast would the rock be going after 2 seconds
Solution:
V = U + at
U = initial Velocity = 0
a = g = 9.8 m/s²
t = 2 m/s
V = ?
V = 0 + (9.8) 2
=> V = 19.6 m/s
19.6m/s. is the correct answer
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Explanation:
V = U + at
U = initial Velocity = 0
a = g = 9.8 m/s²
t = 2 m/s
V = ?
V = 0 + (9.8) 2 => V 19.6 m/s.
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