If a ROM has 15 address lines, then the capacity of data stored is
Answers
Answered by
0
Explanation:
1024*8 means that you have:
1024 locations
8 bits per location
Address Lines:
Assuming that number of address lines (address bits) is n, how can we find n? If n=1, you can only address 2 locations (0 and 1). If n=2, you can address 4 locations (0, 1, 2, and 3). As you can see, number of addressable locations = 2^n.
Given that number of addressable locations = 1024, then 1024=2^n
This means that n=log(1024) to the base 2.
Thus, n=10.
Data Lines:
You have 8 bits for every location, therefore your memory needs a data bus with 8 lines. Every time you read a location (by loading its address on the ...
Similar questions