Math, asked by thespectacularboy, 10 months ago

if a= root 2+1 /root 2-1 and b=1/a then the value of (a+b) is
fast plz

Answers

Answered by tvbaranidharan
0

Answer:

Step-by-step explanation:

Hope it helps friend

a=√2+1/√2-1 * √2+1/√2-1

=(√2+1)^²/2-1 = 2+1+2√2/1

So, a=3+2√2

And b=1/a= 1/3+2√2

a+b= 3+2√2 + 1/3+2√2

= (3+2√2)(3+2√2)

+1/3+2√2

=9+6√2+6√2+8+1/3+2√2

= 18+12√2 / 3+2√2

Pls do mark as brainliest

Answered by technofiroj
0

Answer:

6

Step-by-step explanation:

Given a=root2+1/root2-1 and b=1/a

Hence, b=root2-1/root2+1

then see the attachment...

Attachments:
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