Question

If a = root 2 + 1 ÷ root 2-1
b=1÷a
Find a^2+b^2

Answer 1

Answer:

$= > (\sqrt{2} + 1 \div \sqrt{2} - 1) {}^{2} +( 1 \div a {)}^{2} \\ = >2 + 1 + 2 \div 2 + 1 - 2 + (1 + a){}^{2} \\ = > 5 \div 1 + (1 + \sqrt{2} + 1 \div \sqrt{2} - 1) {}^{2} \\ = > 5 +( 1 + 2 + 1 + 2 \div 2 + 1 - 2) \\ = > 5 +( 1 + 5 \div 1) \\ > 5 + 1 + 5 \\ = > 11$