Question

if a= root 3+1/root 3-1 and b=1/a find the value of a sq-b sq+ab​

Answer 1

a=root3+1/root3-1(root3+1/root3+1)

=(root3+1)^2/3-1

=(root3+1)^2/2

b=1/(root3+1)^2/2

=2/(root3+1)^2

a^2-b^2+ab

=((root3+1)^2/2)^2-((2/(root3+1)^2)^2)+1

=(root3+1)^2/2-2/(root3+1)^2)

=(root3+1)^4-4/2(root 3+1)^2)

so this is ur answer

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Answer 2

Answer:

15

Step-by-step explanation:

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